2x^2-20x+80=0

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Solution for 2x^2-20x+80=0 equation:


Simplifying
2x2 + -20x + 80 = 0

Reorder the terms:
80 + -20x + 2x2 = 0

Solving
80 + -20x + 2x2 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '2'.
2(40 + -10x + x2) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(40 + -10x + x2)' equal to zero and attempt to solve: Simplifying 40 + -10x + x2 = 0 Solving 40 + -10x + x2 = 0 Begin completing the square. Move the constant term to the right: Add '-40' to each side of the equation. 40 + -10x + -40 + x2 = 0 + -40 Reorder the terms: 40 + -40 + -10x + x2 = 0 + -40 Combine like terms: 40 + -40 = 0 0 + -10x + x2 = 0 + -40 -10x + x2 = 0 + -40 Combine like terms: 0 + -40 = -40 -10x + x2 = -40 The x term is -10x. Take half its coefficient (-5). Square it (25) and add it to both sides. Add '25' to each side of the equation. -10x + 25 + x2 = -40 + 25 Reorder the terms: 25 + -10x + x2 = -40 + 25 Combine like terms: -40 + 25 = -15 25 + -10x + x2 = -15 Factor a perfect square on the left side: (x + -5)(x + -5) = -15 Can't calculate square root of the right side. The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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